The combined mean is the average of two or more data groups taken together.
- It is used when each group has a different number of observations and a different mean.
- Instead of finding the average of all values individually, the combined mean is calculated using the mean and the number of items in each group.
Example
- Class A has 20 students with an average score of 70.
- Class B has 30 students with an average score of 80.
\bar{x}=\frac{20\times70+30\times80}{20+30} =\frac{1400+2400}{50} =\frac{3800}{50} =76 The combined mean of the two classes is 76.
Formula
If there are two groups:
- Group 1: Mean =
\bar{x}_1 , Number of observations = n1 - Group 2: Mean =
\bar{x}_2 , Number of observations = n2
Then the combined mean is:
\bar X_{12}=\frac{\bar X_1.N_1+\bar X_2.N_2}{N_1+N_2}
Solved Examples
Example 1: Find out the combined mean when
Solution:
Combined Mean
(\bar X_{12})=\frac{\bar X_1.N_1+\bar X_2.N_2}{N_1+N_2} Combined Mean
(\bar X_{12})=\frac{12\times6+18\times9}{6+9} Combined Mean
(\bar X_{12})=15.6
Example 2: Find out the combined mean when
Series 1 | Series 2 | |
|---|---|---|
Mean | 6 | 7 |
No. of Items | 12 | 14 |
Solution:
Combined Mean
(\bar X_{12})=\frac{\bar X_1.N_1+\bar X_2.N_2}{N_1+N_2} Combined Mean
(\bar X_{12})=\frac{6\times12+7\times14}{12+14} Combined Mean
(\bar X_{12})=6.54
Example 3: Class A has 15 students with mean marks of 60, and Class B has 12 students with mean marks of 48. Calculate the combined mean.
Solution:
For Class A,
\bar X_1=60 , N1 = 15For Class B,
\bar X_2=48 , N2 = 12The required combined mean
\bar X_{12}=\frac{\bar X_1.N_1+\bar X_2.N_2}{N_1+N_2}
\bar X_{12}=\frac{60\times 15+48\times 12}{15+12} Combined Mean
\bar X_{12}=54.67
Example 4: Assume that group 1 has 25 employees with an average salary of ₹82, group 2 has 32 employees with an average salary of ₹45, and group 3 has 77 employees. If the combined salary of the three groups is 70.86, find out the average salary of group 3.
Solution:
For Group 1,
\bar X_1=82 , N1 = 25For Group 2,
\bar X_2=45 , N2 = 32For Group 3, Assume average salary be
\bar X_3=m and it is given that N3 = 77So, Combined Mean
\bar X_{123}=\frac{\bar X_1.N_1+\bar X_2.N_2+\bar X_3.N_3}{N_1+N_2+N_3}
70.86=\frac{(82\times25)+(45\times32)+(m\times77)}{25+32+77}
70.86\times134=2,050+1,440+77m 9,495.24 = 3,490 + 77m
77m = 6005.24
m = ₹77.99 or ₹78
Hence, the average salary of group 3 is ₹78.