Many times, user wants that an instance of a C++ class should not be copied at all. So, the question is how do we achieve this ?
There are three ways to achieve this :
-
Keeping the Copy Constructor and Copy assignment operator as private in the class.
Below is the C++ implementation to illustrate how this can be done.
NOTE: This code does not compile as we cannot copy the object of this class and hence it will show this error.CPP #include <iostream> using namespace std; class Base { int x; public: Base() { } Base(int y): x(y) { } private: // Copy constructor Base(const Base& obj) : x(obj.x) { } // copy assignment operator Base& operator=(const Base& tmp_obj) { x = tmp_obj.x; return *this; } }; int main() { Base b1(10); Base b2(b1); // calls copy constructor b2 = b1; // calls copy assignment operator return 0; }
prog.cpp: In function 'int main()': prog.cpp:18:2: error: 'Base::Base(const Base&)' is private Base(const Base &obj) : x(obj.x) //Copy constructor ^ prog.cpp:33:12: error: within this context Base b2(b1); // Calls copy constructor ^ prog.cpp:22:8: error: 'Base& Base::operator=(const Base&)' is private Base& operator = (const Base& tmp_obj) // copy assignment operator ^ prog.cpp:35:5: error: within this context b2 = b1; // calls copy assignment operator ^ - Inherit a Dummy class with a private copy constructor and a private copy assignment operator.
Below is the C++ implementation to illustrate how this can be done.
CPP #include <iostream> using namespace std; class Dummy { public: Dummy() { } private: Dummy(const Dummy& temp_obj) { } Dummy& operator=(const Dummy& temp_obj) { } }; class Base : public Dummy { int x; public: Base() { } Base(int y) : x(y) { } }; int main() { Base b1(10); Base b2(b1); // Calls copy constructor b2 = b1; // Calls copy assignment operator return 0; }
prog.cpp: In function 'int main()': prog.cpp:12:5: error: 'Dummy::Dummy(const Dummy&)' is private Dummy(const Dummy &temp_obj) ^ prog.cpp:22:7: error: within this context class Base: public Dummy ^ prog.cpp:16:12: error: 'Dummy& Dummy::operator=(const Dummy&)' is private Dummy& operator = (const Dummy &temp_obj) ^ prog.cpp:22:7: error: within this context class Base: public DummyNOTE: This code does not compile as we cannot copy the object of this class and hence it will show this error. - Using Deleted copy constructor and copy assignment operator: Above two ways are quite complex, C++11 has come up with a simpler solution i.e. just delete the copy constructor and assignment operator.
Below is the C++ implementation to illustrate :
CPP // CPP program to demonstrate use Delete copy // constructor and delete assignment operator #include <iostream> using namespace std; class Base { int x; public: Base() { } Base(int y) : x(y) { } Base(const Base& temp_obj) = delete; Base& operator=(const Base& temp_obj) = delete; }; int main() { Base b1(10); Base b2(b1); // Calls copy constructor b2 = b1; // Calls copy assignment operator return 0; }
prog.cpp: In function 'int main()':
prog.cpp:24:15: error: use of deleted function
'Base::Base(const Base&)'
Base b2(b1); // Calls copy constructor
^
prog.cpp:16:5: note: declared here
Base(const Base &temp_obj) = delete;
^
prog.cpp:26:8: error: use of deleted function
'Base& Base::operator=(const Base&)'
b2 = b1; // Calls copy assignment operator
^
prog.cpp:17:11: note: declared here
Base& operator = (const Base &temp_obj) = delete;
^
NOTE: This code does not work as we cannot copy the object of this class and hence it will show this error.
Reference:
https://ariya.io/2015/01/c-class-and-preventing-object-copy