PHP | Imagick displayImage() Function
The Imagick::displayImage() function is an inbuilt function in PHP which is used to displays an image object.
Syntax:
bool Imagick::displayImage( $servername )
Parameters: This function accepts a single parameter $servername which is used to specify the server name.
Return Value: This function returns True on success.
Below programs illustrate the Imagick::displayImage() function in PHP:
Program:
<?php // Create an Imagick object$imagick = new Imagick( // Use displayImage function$imagick->displayImage(5); header("Content-Type: image/jpg"); // Display the output imageecho $imagick->getImageBlob();?> |
Output:
Program 2:
<?php$string = "Computer Science portal for Geeks!"; // creating new image of above String // and add color and background $im = new Imagick();$draw = new ImagickDraw(); // Fill the color in image $draw->setFillColor(new ImagickPixel('green')); // Set the text font size $draw->setFontSize(50); $metrix = $im->queryFontMetrics($draw, $string);$draw->annotation(0, 40, $string);$im->newImage($metrix['textWidth'], $metrix['textHeight'], new ImagickPixel('white')); // Draw the image $im->drawImage($draw); $im->setImageFormat('jpeg'); header("Content-Type: image/jpg"); // Display the output imageecho $im->getImageBlob();?> |
Output:
Reference: http://php.net/manual/en/imagick.displayimage.php
