C# | Random.NextDouble() Method
The NextDouble() Method of System.Random class in C# is used to return a random floating-point number which is greater than or equal to 0.0, and less than 1.0.
Syntax:
public virtual double NextDouble();
Return Value: This method returns a double-precision floating point number which is greater than or equal to 0.0, and less than 1.0.
Below program illustrates the use of NextDouble() Method:
Example 1:
// C# program to illustrate the // Random.NextDouble() Methodusing System; class GFG { // Driver code public static void Main() { // Instantiate random number generator Random rand = new Random(); // Print 10 random floating point numbers Console.WriteLine("Printing 10 random floating point numbers"); for (int i = 0; i < 10; i++) Console.WriteLine("{0} -> {1}", i, rand.NextDouble()); }} |
Output:
Printing 10 random floating point numbers 0 -> 0.0227202852362396 1 -> 0.624568469647583 2 -> 0.0145442797870116 3 -> 0.646489209330869 4 -> 0.967497945748036 5 -> 0.839329582098559 6 -> 0.873648912121378 7 -> 0.16200648022909 8 -> 0.66018275761054 9 -> 0.0837694853934317
Example 2:
// C# program to illustrate the // Random.NextDouble() Methodusing System; class GFG { // Driver code public static void Main() { // Instantiate random number generator Random rand = new Random(); // Instantiate an array of double double[] a = new double[10]; // Store random floating point // numbers in the array for (int i = 0; i < 10; i++) a[i] = rand.NextDouble(); // Print 10 random floating point numbers Console.WriteLine("Printing 10 random "+ "floating point numbers"); for (int i = 0; i < 10; i++) Console.WriteLine("{0} -> {1}", i, a[i]); }} |
Output:
Printing 10 random floating point numbers 0 -> 0.853536825558886 1 -> 0.741455778359182 2 -> 0.496043408986201 3 -> 0.0975164361752181 4 -> 0.120282317567748 5 -> 0.57163705703413 6 -> 0.749181974562435 7 -> 0.684014179596684 8 -> 0.691246760865323 9 -> 0.888019556127498
Reference:
