How to find last value from any table in SQL Server
We could use LAST_VALUE() in SQL Server to find the last value from any table. LAST_VALUE() function used in SQL server is a type of window function that results the last value in an ordered partition of the given data set.
Syntax :
SELECT *, FROM tablename LAST_VALUE ( scalar_value ) OVER ( [PARTITION BY partition_expression ] ORDER BY sort_expression [ASC | DESC] ) AS columname ;
Where the terminologies description as follows.
scalar_value –
scalar_value is a value analyzed against the value of the last row in an ordered partition of the given data set.
PARTITION BY –
PARTITION BY clause is optional, it differs the rows of the given data set into partitions where the LAST_VALUE() function is used.
ORDER BY –
ORDER BY clause defines the order of the rows in each partition where the LAST_VALUE() function is used.
Example-1 :
Let us suppose we have a table named ‘geekdemo’;
SELECT Name, City, Year FROM [geekdemo] ;
| Name | City | Year |
|---|---|---|
| Ankit | Delhi | 2019 |
| Babita | Noida | 2017 |
| Chetan | Noida | 2018 |
| Deepak | Delhi | 2018 |
| Isha | Delhi | 2019 |
| Khushi | Noida | 2019 |
| Megha | Noida | 2017 |
| Parul | Noida | 2017 |
Example-2 :
LAST_VALUE() without PARTITION BY clause :
SELECT TOP 1000 Name, Year, LAST_VALUE(City) OVER (ORDER BY City ASC ) AS Last_City FROM geekdemo;
Output :
| Name | Year | Last_City |
|---|---|---|
| Deepak | 2018 | Delhi |
| Isha | 2019 | Delhi |
| Ankit | 2019 | Delhi |
| Babita | 2017 | Noida |
| Chetan | 2018 | Noida |
| Khushi | 2019 | Noida |
| Megha | 2017 | Noida |
| Parul | 2017 | Noida |
Example-3 :
LAST_VALUE() with PARTITION BY clause :
SELECT Name, Year, LAST_VALUE(City) OVER (PARTITION BY Year ORDER BY City ASC) AS Last_City FROM geekdemo;
Output :
| Name | Year | Last_City |
|---|---|---|
| Babita | 2017 | Noida |
| Megha | 2017 | Noida |
| Parul | 2017 | Noida |
| Deepak | 2018 | Delhi |
| Chetan | 2018 | Noida |
| Isha | 2019 | Delhi |
| Ankit | 2019 | Delhi |
| Khushi | 2019 | Noida |
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