🔥 ข่าวด่วน: web//https://www.geeksforgeeks.org/handling ajax request in django

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Introduction

This tutorial explains how to carry out a ajax request in Django web framework. We will create a simple post-liking app as a part of example.

Glossary

Project Initialization
Create models
Create views
Write urls
Carry out request with Jquery AJax.
Register models to admin and add some posts.

Implementation:

1. Initiate the Django Project – Here I am assuming that you are done with Django Installation.

To Create a Django Project execute:

$ django-admin startproject django_example

After creating a project we need to create a django app. To create an app say “post” execute the following:
```
$ cd django_example
$ python manage.py startapp post
```
Go to django_example/settings.py add the post app
Now you will have files something like this:

directory_structure

2. Create models: To create models, go to post directory and open models.py .

In models.py, first create post table. To create post table you’ll need to write:

    class Post(models.Model):
        post_heading = models.CharField(max_length=200)
        post_text = models.TextField()
            def __unicode__(self):      # If python2 use __str__ if python3
                 return unicode(self.post_heading)

Then In models.py, create like table. To create like table you’ll need to write:

    class Like(models.Model):
        post = models.ForeignKey(Post)

Make Migration and migrate step:

$ python manage.py makemigrations
$ python manage.py migrate

After completing this steps, we have our database tables ready to use.

3. Create Views:

To create views, we need to go to post directory and open views.py

First, import Previously created Models and HTTPresponse

      from .models import Post, Like
      from django.http import HttpResponse

Create index view to render all the posts. Code sample:

    def index(request):
        posts = Post.objects.all()  # Getting all the posts from database
        return render(request, 'post/index.html', { 'posts': posts })

Create likePost view to like a post. This view will be called when we will hit a “like button”. Code sample:

    def likePost(request):
        if request.method == 'GET':
               post_id = request.GET['post_id']
               likedpost = Post.objects.get(pk=post_id) #getting the liked posts
               m = Like(post=likedpost) # Creating Like Object
               m.save()  # saving it to store in database
               return HttpResponse("Success!") # Sending an success response
        else:
               return HttpResponse("Request method is not a GET")

Once our view get created we will move to write template and jQuery to perform ajax request.

4. Create URLs:

To create urls, open django_example/urls.py. Your django_example/urls.py should look something like this:

from django.conf.urls import include, url
from django.contrib import admin
urlpatterns = [
     url(r'^admin/', admin.site.urls),
     url(r'^', include('post.urls')),   # To make post app available at /
   ]

To create urls, create file post/urls.py. Your post/urls.py should look something like this:

from django.conf.urls import url
from . import views
urlpatterns = [
        url(r'^$', views.index, name='index'),  # index view at /
        url(r'^likepost/$', views.likePost, name='likepost'),   # likepost view at /likepost
   ]

5. Making templates and carrying out ajax request:

Create a file post/templates/post/index.html. Code sample:

<!DOCTYPE html>
<html>
<head>
    <title>Like Post App</title>
</head>
<body>
    <p id="message"></p>
    {% for post in posts %}
    <h3>{{ forloop.counter }}) {{ post.post_heading }}</h3>
    <p>{{ post.post_text }} </p>
    <a class="likebutton" id="like{{post.id}}" href="#" data-catid="{{ post.id }}">Like</a>
    {% endfor %}
    <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.0/jquery.min.js"></script>
    <script type="text/javascript">
    $('.likebutton').click(function(){
    var catid;
    catid = $(this).attr("data-catid");
    $.ajax(
    {
        type:"GET",
        url: "/likepost",
        data:{
                 post_id: catid
        },
        success: function( data ) 
        {
            $( '#like'+ catid ).remove();
            $( '#message' ).text(data);
        }
     })
});
</script>
</body>
</html>
Basically, what we are doing here is - we are making an ajax get request -> /likepost?post_id=<id_of_liked_post>

6. To Register models to admin and add some posts:

Open post/admin.py.
Import Models to admin.py.

from .models import Post, Like

admin.site.register(Post)
admin.site.register(Like)

Now add some posts using django default admin portal. Visit http://localhost:8000/ to view and like posts. I also have added this sample app to my github which you may use for reference.

References:

https://docs.djangoproject.com/en/1.9/intro/tutorial01/

Happy Djangoing !!!

This blog is written by Anshul Singhal. If you also wish to showcase your blog here, please see GBlog for guest blog writing on GeeksforGeeks.

My Personal Notes

Oct	NOV	Dec
	03
2019	2020	2021

Handling Ajax request in Django

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