Given two coordinates of a line starting is (x1,y1) and ending is (x2,y2) find out the mid-point of a line.
Examples :
Input : x1 = â1, y1 = 2,
x2 = 3, y2 = â6
Output : 1,â2
Input : x1 = 6.4, y1 = 3
x2 = â10.7, y2 = 4
Output : â2.15, 3.5
The Midpoint Formula: The midpoint of two points, (x1, y2) and (x2, y2) is the point M found by the following formula: M = ((x1+x2)/2 , (y1+y2)/2)
C++
// C++ program to find // the midpoint of a line #include<iostream> using namespace std; // function to find the // midpoint of a line void midpoint(int x1, int x2, int y1, int y2) { cout << (float)(x1+x2)/2 << " , "<< (float)(y1+y2)/2 ; } // Driver Function to test above int main() { int x1 =-1, y1 = 2 ; int x2 = 3, y2 = -6 ; midpoint(x1, x2, y1, y2); return 0; } |
Java
// Java program to find // the midpoint of a line import java.io.*; class GFG { // function to find the // midpoint of a line static void midpoint(int x1, int x2, int y1, int y2) { System.out.print((x1 + x2) / 2 + " , " + (y1 + y2) / 2) ; } // Driver code public static void main (String[] args) { int x1 =-1, y1 = 2 ; int x2 = 3, y2 = -6 ; midpoint(x1, x2, y1, y2); } } // This code is contributed by vt_m. |
Python3
# Python3 program to find # the midpoint of a line # Function to find the # midpoint of a line def midpoint(x1, x2, y1, y2): print((x1 + x2) // 2, " , ", (y1 + y2) // 2) # Driver Code x1, y1, x2, y2 = -1, 2, 3, -6midpoint(x1, x2, y1, y2) # This code is contributed by Anant Agarwal. |
C#
// C# program to find // the midpoint of a line using System; class GFG { // function to find the // midpoint of a line static void midpoint(int x1, int x2, int y1, int y2) { Console.WriteLine((x1 + x2) / 2 + " , " + (y1 + y2) / 2) ; } // Driver code public static void Main () { int x1 =-1, y1 = 2 ; int x2 = 3, y2 = -6 ; midpoint(x1, x2, y1, y2); } } // This code is contributed by vt_m. |
PHP
<?php // PHP program to find // the midpoint of a line // function to find the // midpoint of a line function midpoint($x1, $x2, $y1, $y2) { echo((float)($x1 + $x2)/2 . " , " . (float)($y1 + $y2)/2) ; } // Driver Code $x1 = -1; $y1 = 2 ; $x2 = 3; $y2 = -6 ; midpoint($x1, $x2, $y1, $y2); // This code is contributed by Ajit. ?> |
Output :
1 , -2
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Improved By : jit_t
