Many times while working with Python strings, we have a problem in which we need to remove certain characters from strings. This can have application in data preprocessing in Data Science domain and also in day-day programming. Lets discuss certain ways in which we can perform this task.
Method #1 : Using loop + punctuation string
This is brute way in which this task can be performed. In this, we check for the punctuations using raw string which contain punctuations and then we construct string removing those punctuations.
# Python3 code to demonstrate working of # Removing punctuations in string # Using loop + punctuation string # initializing string test_str = "Gfg, is best : for ! Geeks ;" # printing original string print("The original string is : " + test_str) # initializing punctuations string punc = '''!()-[]{};:'"\, <>./?@#$%^&*_~''' # Removing punctuations in string # Using loop + punctuation string for ele in test_str: if ele in punc: test_str = test_str.replace(ele, "") # printing result print("The string after punctuation filter : " + test_str) |
The original string is : Gfg, is best : for ! Geeks ; The string after punctuation filter : Gfg is best for Geeks
Method #2 : Using regex
The part of replacing with punctuation can also be performed using regex. In this, we replace all punctuation by empty string using certain regex.
# Python3 code to demonstrate working of # Removing punctuations in string # Using regex import re # initializing string test_str = "Gfg, is best : for ! Geeks ;" # printing original string print("The original string is : " + test_str) # Removing punctuations in string # Using regex res = re.sub(r'[^\w\s]', '', test_str) # printing result print("The string after punctuation filter : " + res) |
The original string is : Gfg, is best : for ! Geeks ; The string after punctuation filter : Gfg is best for Geeks
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